Multiple Variable Assignments In One Row
Solution 1:
The short answer is yes, that statement will assign 5
to each of 4 variables a
, b
, c
and d
. But, contrary to what was said, doesn't assign 5
to d
, and then the value of d
to c
, but it will assign the same value to each variables, starting from the right-hand side. To be more clear, your statement:
var a, b,c, d;
a = b =c= d =5;
It's equivalent to:
var d = 5;
var c = 5;
var b = 5;
var a = 5;
Not to:
var d = 5;
var c = d;
var b = c;
var a = b;
It's a subtle but important difference: in the first case, JavaScript just sets a value to all the variables. In the second case, JavaScript set a value to all the variables but also get the value of three variables (the value of a
is not assigned anywhere).
A simple code that will show that:
// `this` is the global object if you run this code in the global scope.// In the browsers the global object is `window`.Object.defineProperties(this, {
"a": {
get: function() {
console.log("get a");
},
set: function(value) {
console.log("set a");
}
},
"b": {
get: function() {
console.log("get b");
},
set: function(value) {
console.log("set b");
}
},
"c": {
get: function() {
console.log("get c");
},
set: function(value) {
console.log("set c");
}
},
"d": {
get: function() {
console.log("get d");
},
set: function(value) {
console.log("set d");
}
}
});
b = c = d = 5;
a = b;
On the console you should have:
set d
set c
set b
get b
set a
As you can see for the statement b = c = d = 5
JS only set the variable, and call both set
and get
on b
, because the statement a = b
.
This distinction is very important, because if you define some getter for your property and you're not aware of this behavior, you will end up with unexpected bug using multiple variable assignments.
Solution 2:
For the most part yes, but consider the following scenario:
Object.defineProperty(this, "b", { value : 6, writable : false });
var a, c, d;
a = b = c = d = 5;
console.log(a); // 5console.log(b); // 6console.log(c); // 5console.log(d); // 5
Solution 3:
The answer is yes.
a=b=c=d=e=f=g=h=4; // all get to be 4
a=b=c=d=e=f=g=h={ p1:"1", p2:"2" }; // same object for all
a.p3 = "3";
console.log((a==b && b==c && c==d && d==e), f); // condition is true, f is now // {// p1:"1",// p2:"2",// p3:"3"// }
Solution 4:
You have only to try it to know the answer: Yes.
The reason it works like that is that assignment takes whatever is on the right-hand side of the equals sign and assigns that value to the variable on the left-hand side.
So 5
is assigned to d
; then the value of d
is assigned to c
and so on.
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