Regex, Removing Recurring Characters But Keeping At Least One January 13, 2024 Post a Comment I'm using this html = html.replace(/([^0-9]).*?\1/ , ''); but it's not quite doing what I'm trying to do. I want to replace the doubles within a string, but still keep at least oSolution 1: THink you mean this,str.replace(/(.)\1+/g, '$1') Copyor str.replace(/([^0-9])\1+/g, '$1') CopyBaca JugaJs Regexp To Replace < And > Inside Element AttributesHow Do I Quantify A Group In Javascript's Regex?How To Place The Caret Where It Previously Was After Replacing The Html Of A Contenteditable Div? Share You may like these postsRemove All Instances Of A Character In A String With Something Else JavascriptJavascript Regex: Bolding Needles In A HaystackReplace With Previous String In A Json ArrayHow Do I Perform A Javascript Match With A Pattern That Depends On A Variable? Post a Comment for "Regex, Removing Recurring Characters But Keeping At Least One"
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