Regex, Removing Recurring Characters But Keeping At Least One January 13, 2024 Post a Comment I'm using this html = html.replace(/([^0-9]).*?\1/ , ''); but it's not quite doing what I'm trying to do. I want to replace the doubles within a string, but still keep at least oSolution 1: THink you mean this,str.replace(/(.)\1+/g, '$1') Copyor str.replace(/([^0-9])\1+/g, '$1') CopyBaca JugaSplit String By Html Entities?Js Regexp To Replace < And > Inside Element AttributesHow Do I Quantify A Group In Javascript's Regex? Share You may like these postsSys.webforms.pagerequestmanager Is Undefined Error In Ie11, Working Fine In Ie10 And BelowJavascript 2d Array Generation Doesn't Work As IntendedInfinite Loop When Trying To Make Angularjs Display A PromiseFunction Animate({ Draw1, Duration1 }) {... Causes Expected Identifier (script1010) Error In Ie11 - Object Destructuring Support In Ie Post a Comment for "Regex, Removing Recurring Characters But Keeping At Least One"
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