How To Make Array.foreach(asyncfn) Synchronized?
Solution 1:
Like this?
for (let x of a) {
await fn(x);
}
Or if you really dislike creating a separate fn
:
for (let x of a) {
await (async v => {
...
})(x);
}
You could even add it to Array.prototype
:
Array.prototype.resolveSeries = asyncfunction(fn) {
for (let x ofthis) {
awaitfn(x);
}
}
// Usage:await a.resolveSeries(fn);
// Or:await a.resolveSeries(async x => {
...
});
Solution 2:
I have used a library called async. There a function called eachSeries
. It takes an array, an async function, and a callback. The function is called on each item for the array.
This question can open a rabbit hole of complexity. You will need to be careful that your async function doesn't make an asynchronous call. The library provides a callback that can be useful in this case.
function asyncFunction(val, callback) {
return (function() {
//do stuffcallback();
})();
}
The callback will initiate the a call on the next item in the array.
Solution 3:
I've been using this function for a while, in case if a dedicated library is not desired:
// usage: // array.asyncEach(function(item, resume) {// do something...// console.log(item); // resume(); // call `resume()` to resume the cycle// }//// unless resume() is called, loop doesn't proceed to the next itemArray.prototype.asyncEach = function(iterator) {
var list = this,
n = list.length,
i = -1,
calls = 0,
looping = false;
var iterate = function() {
calls -= 1;
i += 1;
if (i === n) return;
iterator(list[i], resume);
};
var loop = function() {
if (looping) return;
looping = true;
while (calls > 0) iterate();
looping = false;
};
var resume = function() {
calls += 1;
if (typeofsetTimeout === 'undefined') loop();
elsesetTimeout(iterate, 1);
};
resume();
};
Perform any async tasks inside the function, and call resume()
when you are done.
I don't remember where did I get this function from.
Solution 4:
Is there anyspecific event on which these function will be called ?
if yes can be achieved through **closure**in javascript.
right now your function will be called with last value in array when you invoke it
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